Indiana’s Big Ten Tournament itinerary was cemented on Sunday night.
IU will open the conference tournament as the No. 10 seed, facing No. 7 Iowa on Thursday at 6:30 at the Verizon Center in Washington D.C. The Hawkeyes won the only regular season meeting between the two teams, knocking off the Hoosiers, 96-90, in overtime on Feb. 21.
IU avoided the No. 11 seed and a Wednesday matchup with No. 14 Rutgers when Nebraska lost to Michigan, 93-57, on Sunday night. Indiana won its regular season finale over Ohio State, 96-92, on Saturday afternoon.
“With a team like us, we can get hot fast,” IU guard James Blackmon Jr. said. “It can be a start to a run if we all just buy in.”
The Hoosiers haven’t won two Big Ten Tournament games since 2003. Should they defeat the Hawkeyes, they’d earn a quarterfinals date with No. 2 Wisconsin at 6:30 p.m. Friday.
IU has won two of its last three games after dropping five in a row. Iowa rides a four-game winning streak into Washington, a run that began with the win over Indiana two weeks ago.